A first order reaction has a rate constant of 2.303 × 10 − 3 s − 1 ×10-3 s-1. The time required for 40 g of this reactant to reduce to 10 g will be [Given that log 10 2 = 0 . 3010 log102=0.3010]

 

 Question:  Explanations are 100% from NCERT | [Difficult level: Easy] From NCERT NEET 2019

A first order reaction has a rate constant of 2.303$\times {10}^{-3}{s}^{-1}$. The time required for 40 g of this reactant to reduce to 10 g will be [Given that ${\log }_{10}2=0.3010$]

(1) 230.3 s

(2) 301 s

(3) 2000 s

(4) 602 s