Class 11 | Physics | chapter 1 | Units And Measurements Important MCQs *

Ruhul Amin Alig

Question.

Answer

Question. From NCERT

The dimensional formula of the coefficient of thermal conductivity is :

1. $[M^{1} L^{1} T^{- 3} K^{- 1}]$

2. $[M^{3} L^{- 1} T^{- 3} K]$

3. $[M^{1} L^{- 3} T^{- 1} K^{- 1}]$

4. $[M^{1} L^{1} T^{- 3} K]$

Answer

Correct option is

$[M L T^{- 3} k^{- 1}]$

The for the coefficient of thermal conductivity is
$K_{t h} = \frac{Q Δ x}{A Δ T t}$
TRICK
Thermal Conductivity-
Speed of Heat Flow per unit Area and Temperature
Dimensional formula of $K_{t h}$
$[K_{t h}] = \frac{[ H e a t ] . [ l e n g t h ]}{[ A r e a ] . [ T e m p e r a t u r e ] . [ t i m e ]}$
$[K_{t h}] = \frac{[ M L ^{2} T ^{- 2} ] . [ L ]}{[ L ^{2} ] . [ K ] . [ T ]}$
$[K_{t h}] = [M L T^{- 3} K^{- 1}]$
The correct option is D.

Question. From Derived NCERT

If L,Q,R represent inductance, charge and resistance respectively, the units of

[This question includes concepts from 12th syllabus]

1. $\frac{Q R}{L}$ will be those of current

2. $\frac{Q^{2} R^{3}}{L^{2}}$ will be those of energy

3. $\frac{Q L}{R}$ will be those of current

4. $\frac{Q^{3} R^{2}}{L}$ will be those of power

Answer

Answer is 1

solution

Question.

Answer

Question.From NCERT

The dimension of $\frac{1}{2} ε_{0} E^{2}$ ( $ε_{0}$ is the permittivity of free space and $E$ is electric field), is

$[M L^{2} T^{- 1}]$

$[M L^{- 1} T^{- 2}]$

$[M L^{2} T^{- 2}]$

$[M L T^{- 1}]$

Answer

Correct option is

$[M L^{- 1} T^{- 2}]$

We know that the given equation gives the energy

density for a capacitor. Dimensions of energy density

can be found as Electrical Energy divided by

Volume, or $\frac{M L ^{2} T ^{- 2}}{L ^{3}} = M L^{- 1} T^{- 2}$

Question.

The quantity $\frac{1}{2} \in_{0} E^{2}$ has dimensional formula same as [This question includes concepts from 12th syllabus]

1. $\frac{1}{2} C V^{2}$

2. $\frac{1}{2} L I^{2}$

3. $\frac{1}{2} \frac{B^{2}}{μ_{0}}$

Answer

Question.From NCERT PMT - 1989

Light year is a unit of

(1) Time

(2) Mass

(3) Distance

(4) Energy

Answer

Question.From NCERT

The magnitude of any physical quantity:

(1) depends on the method of measurement.

(2) does not depend on the method of measurement.

(3) is more in the SI system than in the CGS system.

(4) is directly proportional to the fundamental units of mass, length and time.

Answer

Question.From NCERT PMT - 1990

Which of the following is not equal to watt ?

(1) Joule/second

(2) Ampere $\times$ volt

(3) (Ampere)2 $\times$ ohm

(4) Ampere/volt

Answer

Question.From NCERT PMT - 1984

$N e w t o n - s e c o n d (N \cdot s)$ is the unit of

Velocity

Angular momentum

Momentum

Energy

Answer

Correct option is

Momentum

We know that:
$I m p u l s e = c h a n g e i n m o m e n t u m = F \times t$ .

So the unit of momentum will be equal to $N e w t o n - s e c$ .

Question. From NCERT

Which one of the following quantities has not been expressed in proper units ?

$\frac{S t r e s s}{S t r a i n} = N / m^{2}$

$S u r f a c e t e n s i o n = N / m$

$E n e r g y = k g - m / s$

$P r e s s u r e =$ $N / m^{2}$

Answer

Correct option is

$E n e r g y = k g - m / s$

Stress has the units of Force/Area = $N / m^{2}$ ,

while strain (= $Δ l / l$ ) is dimensionless. So option A is correct.

Surface tension is Force/Length, thus $N / m$ , hence B is also correct.

Energy has the units of $[M L^{2} T^{- 2}]$ ,
hence the units have to be $k g m^{2} / s^{2}$ . Thus C is incorrect option.

Pressure is Force/Area = $N / m^{2}$ , thus D is again correct.

Question.From NCERT

One second is equal to :

(1) 1650763.73 time periods of $K r$ clock

(2) 652189.63 time periods of $K r$ clock

(3) 1650763.73 time periods of $C s$ clock

(4) 9192631770 time periods of $C s$ clock

Answer

Question. From NCERT PMT - 1985

The unit of power is :

(1) Joule

(2) Joule per second only

(3) Joule per second and watt both

(4) Only watt

Answer

Question.From NCERT PMT - 1984

SI unit of pressure is

(1) Pascal

(2) $D y n e s / c m^{2}$

(3) cm of Hg

(4) Atmosphere

Answer

Question.From NCERT PMT - 1992

The unit of Stefan's constant $σ$ is : [This question includes concepts from Thermal Properties of Matter chapter]

(1) $W m^{- 2} K^{- 1}$

(2) $W m^{2} K^{- 4}$

(3) $W m^{- 2} K^{- 4}$

(4) $W m^{- 2} K^{4}$

Answer

Correct option is

$W m^{- 2} K^{- 4}$

Stefan's law is $E = σ (T^{4})$
$\Rightarrow σ = \frac{E}{T ^{4}}$

where, $E = \frac{E n e r g y}{A r e a \times T i m e} = \frac{W a t t}{m ^{2}}$

$σ = \frac{W a t t - m ^{2}}{k ^{4}} = W a t t - m^{- 2} k^{- 4}$

Question.From NCERT PMT - 1993

In $S = a + b t + c t^{2}$ , S is measured in metres and t in seconds. The unit of c is

(1) None

(2) m

(3) $m s^{- 1}$

(4) $m s^{- 2}$

Answer

Question.From NCERT PMT - 1990

Joule-second is the unit of :

(1) Work

(2) Momentum

(3) Pressure

(4) Angular momentum

Answer

Correct option is

Angular momentum

Joule is a unit of energy and second

is the unit of time.
Thus, $J o u l e \times s e c o n d$ has dimensions
$M L^{2} T^{- 2} \times T = M L^{2} T^{- 1}$
Now, energy cannot be the answer
since energy has Joule as its unit
and cannot be Joule-seconds.
Momentum can't be the answer as
momentum is force X time which
has dimensions $M L T^{- 1}$
Angular momentum is given by cross
product of linear momentum and radius
vector thus it has dimensions
$M L T^{- 1} \times L = M L^{2} T^{- 1}$ , which is the correct answer.
Finally, Power is force times velocity,
so its dimensions are $M L T^{- 2} \times L T^{- 1} = M L^{2} T^{- 3}$

Question.

Electron volt is a unit of

(1) Charge

(2) Potential difference

(3) Momentum

(4) Energy

Answer

Correct option is

Energy

The electron volt (symbol eV; also written electronvolt)

is a unit of energy equal to approximately

1.602 $\times$ 10 $^{- 19}$ joule (SI unit J).

By definition, it is the amount of
energy gained by the charge of a
single electron moved across an
electric potential difference of one volt.

Hence, the correct option is $B$

Question.From NCERT

Temperature can be expressed as a derived quantity in terms of any of the following

1. Length and mass

2. Mass and time

3. Length, mass, and time

4. None of these

Answer

Correct option is

None of these

Temperature is a fundamental quantity,

so it can not be expressed as a

derived quantity in terms of length, mass and time.
The correct option is D.

Question.From NCERT

The unit of energy is
(A) J/s
(C) kilowatt
(B) watt x day
(D) g cm/sec

Answer

Answer is B

Question.From NCERT

Which is the correct unit for measuring nuclear radii

(1) Micron

(2) Millimetre

(3) Angstrom

(4) Fermi

Answer

Question.From NCERT

Volt/metre is the unit of

(1) Potential

(2) Work

(3) Force

(4) Electric field intensity

Answer

Correct option is

Electric field intensity

The electric field intensity is given as:
$E = - \frac{d V}{d x}$

Its unit is $v o l t s / m e t r e$

Question.From NCERT PMT - 1983

The unit of self inductance of a coil is

(1) Farad

(2) Henry

(3) Weber

(4) Tesla

Answer

Correct option is

Henry

The self-inductance of a coil is given as:
$L = \frac{ϕ}{I}$

$= \frac{W b}{A} = H e n r y$

Question.From NCERT PMT - 2005

If the unit of length and force be increased four times, then the unit of energy is

1. Increased 4 times

2. Increased 8 times

3. Increased 16 times

4. Decreased 16 times

Answer

Question.From NCERT

Ampere - hour is a unit of

(1) Quantity of electricity

(2) Strength of electric current

(3) Power

(4) Energy

Answer

Correct option is

quantity of electricity

Ampere-hour is the unit of quantity of electricity or quantity of electric charge.
Power is measured in Watt.
Energy is measured in Joules.
Strength of current ia measured in Amperes.

Hint: Use principle of Homogeneity and remember that rate of flow of charge through a point is known as current.
Formula used: $I = \frac{Q}{t}$ $I = \frac{Q}{t}$ $I = \frac{Q}{t}$ $I = \frac{Q}{t}$
$I = \frac{Q}{t}$ $I = \frac{Q}{t}$ $I = \frac{Q}{t}$ Here Q is the charge flowing through a point at a time period t.

$I = \frac{Q}{t}$ $I = \frac{Q}{t}$ $I = \frac{Q}{t}$ $I = \frac{Q}{t}$ $I = \frac{Q}{t}$
Complete step by step solution:
We know Ampere is a unit of current and its dimension is $M^{0} L^{0} T^{0} A^{1}$
So dimension of Ampere hour is $M^{0} L^{0} T^{1} A^{1}$

Also, since current $I = \frac{Q}{t}$ ; $Q = I \times t$

we can see that charge and Ampere hour has a same dimension of $M^{0} L^{0} T^{1} A^{1}$
Using the principle of homogeneity we can say that Ampere hour represents the amount of charge.

Just like how mass is a measure of the amount of matter in a system, charge can be seen as a measure of the amount of electrified matter or the Quantity of electricity present in the system.

So we can conclude that ampere hour is a measure of quantity of electricity (which is equivalent to the amount of electric charge)

Thus, the correct option is C.

Additional Information:

The SI unit of charge is coulomb.

1 ampere hour is the amount of charge transferred if 1A current passes through a region for 1hour.

Since coulomb represent the flow in seconds

1 Ampere hour $= 60 \times 60 C$

$1 A h = 3600 C$ (Ah is a symbol used for ampere hour.)

Note: The principle of homogeneity is not true for all cases .Since the ratios, constants, or trigonometric quantities have no dimension, their presence or absence in an equation cannot be determined.
Also, sometimes comparing dimensions would not give a correct significance of a quantity. For example: Though Torque and Energy have the same dimension, we cannot say - Joules represent the Moment of force on a body.

Question.From NCERT

The unit of specific resistance is

(1) Ohm / cm2

(2) Ohm / cm

(3) Ohm - cm

(4) (Ohm - cm)-1

Answer

solution

Question.From NCERT

The binding energy of a nucleon in a nucleus is of the order of a few

(1) eV

(2) Ergs

(3) MeV

(4) Volts

Answer

Correct option is

Mega electron volt (MeV)

Atomic energies are of order of electron volts and kilo electron volts but binding energy of nucleus that is energy required to keep the nucleus together has very high magnitude. It is of the order of Mega electron volt.

Question.From NCERT

If u1 and u2 are the units selected in two systems of measurement and n1 and n2 their numerical values, then

(1) $n_{1} u_{1} = n_{2} u_{2}$

(2) $n_{1} u_{1} + n_{2} u_{2} = 0$

(3) $n_{1} n_{2} = u_{1} u_{2}$

(4) $(n_{1} + u_{1}) = (n_{2} + u_{2})$

Answer

Question. From NCERT

Universal time is based on :

(1) Rotation of the earth on its axis

(2) Earth's orbital motion around the Sun

(3) Vibrations of cesium atom

(4) Oscillations of quartz crystal

Answer

Correct option is

orbital motion of the earth around the sun

Universal Time (UT) is a time standard based on Earth's rotation.

Based on the rotation of the Earth, time can be measured by

observing celestial bodies crossing the meridian every day.

Astronomers found that it was more accurate to establish time

by observing stars as they crossed a meridian rather than by

observing the position of the Sun in the sky. The rotation of the

Earth and UT are monitored by the International Earth Rotation

and Reference Systems Service (IERS).

Question. From NCERT PMT - 1984

Unit of stress is

(1) $N / m$

(2) $N - m$

(3) $N / m^{2}$

(4) $N - m^{2}$

Answer

Question.From NCERT

Unit of magnetic moment is

(1) $A m p e r e - m e t r e^{2}$

(2) $A m p e r e - m e t r e$

(3) $W e b e r - m e t r e^{2}$

(4) $W e b e r / m e t r e$

Answer

Question.From NCERT

One pico Farad is equal to

(1) $10^{- 24} F$

(2) $10^{- 18} F$

(3) $10^{- 12} F$

(4) $10^{- 6} F$

Answer

Question.From NCERT PMT - 1993

In SI, Henry is the unit of

(1) Self inductance

(2) Mutual inductance

(3) (1) and (2) both

(4) None of the above

Answer

Question.From NCERT PMT - 1986

The unit of $e . m . f .$ is

(1) Joule

(2) Joule-Coulomb

(3) Volt–Coulomb

(4) Joule/Coulomb

Answer

Question.

The unit of e.m.f. of a cell is:

dyne

volt

ampere

joule

Answer

Correct option is

volt

Electromotive force or e.m.f is defined as the battery's

energy per Coulomb of charge passing through it.

like other measures of energy per charge emf has

SI unit of volts , equivalent to joules per coulomb.

Question.From NCERT

Unit of self inductance is [This question includes concepts from 12th syllabus]

(1) $\frac{N e w t o n - \sec o n d}{C o u l o m b \times A m p e r e}$

(2) $\frac{J o u l e / C o u l o m b \times S e c o n d}{A m p e r e}$

(3) $\frac{V o l t \times m e t r e}{C o u l o m b}$

(4) $\frac{N e w t o n \times m e t r e}{A m p e r e}$

Answer

Self-inductance of a coil is defined as the phenomenon due to which an emf is induced in a coil when the magnetic flux of coil , linked with the coil changes or current in coil changes . Its S.I. unit is $H e n r y (H)$

Question.From NCERT

To determine Young's modulus of a wire, the formula is $Y = \frac{F}{A} \times \frac{L}{Δ L};$ where L = length, A = area of cross-section of the wire, $Δ L =$ change in length of the wire when stretched with a force F. The conversion factor to change it from CGS to MKS system is

(1) 1

(2) 10

(3) 0.1

(4) 0.01

Answer

Hint: Young’s modulus is dependent on factors such as force, length and are inversely dependent on factors such as area. Now, we know the SI units of the same which are in the MKS system. To find the factor, equate the units in CGS system and MKS system and find the factor by which it varies.

Complete Step by Step Solution:
Young’s modulus, also called as modulus of elasticity, is the measure of the tensile stiffness of the given material. It also measures the stiffness of the material when there is a force applied on it which causes the change in length due to compression or expansion. Young’s modulus directly depends upon the force applied on the body and inversely varies upon the area of the surface where the force is applied. This can be represented mathematically as,

Y = \frac{F L}{A Δ L}

Where, F is the force applied and A is the area of the surface.
Force in the CGS unit is measured in dyne and area is measured in centimeters. In the MKS system, the force is measured as Newton’s and area and change in length are measured in meters. Using this the units for young’s modulus is given as,

\Rightarrow Y = d y n e / c m^{2}

in CGS unit and

\Rightarrow Y = N / m^{2}

in MKS units
Now, taking the CGS equation, we know that

1 d y n e = 10^{- 5} N

. Substituting this in the equation we get,

\Rightarrow Y = \frac{10^{- 5} N}{c m^{2}}

We know that

1 c m = 10^{- 2} m

. Substituting this , we get

\Rightarrow Y = \frac{10^{- 5} N}{{(10^{- 2} m)}^{2}}

On further simplification, we get,

\Rightarrow Y = \frac{10^{- 5} N}{10^{- 4} m^{2}}

Taking the common term to the numerator ,we get

\Rightarrow Y = \frac{10^{- 5 + 4} N}{m^{2}}

\Rightarrow Y = \frac{10^{- 5 + 4} N}{m^{2}} = \frac{10^{- 1} N}{m^{2}}

Hence,

\frac{1 d y n e}{c m^{2}} = 0.1 \frac{N}{m^{2}}

Therefore, option (c) is the right answer for the given question.

Note: The CGS system is abbreviated as Centimeter-Gram-Second system, which is a type of Standard Unit system that is quite useful in measuring small quantities in chemical fields. MKS system abbreviated as Meter-Kilogram-Second is used for standard measurements globally across various fields.

Question.From NCERT PMT - 1994

Young's modulus of a material has the same units as

(1) Pressure

(2) Strain

(3) Compressibility

(4) Force

Answer

Question.From NCERT PMT - 1997

The units of modulus of rigidity are

(1) $N - m$

(2) $N / m$

(3) $N - m^{2}$

(4) $N / m^{2}$

Answer

Question.From NCERT

The unit of absolute permittivity is

(1) $F m$ (Farad-metre)

(2) $F m^{- 1}$ (Farad/metre)

(3) $F m^{- 2}$ (Farad/ $m e t r e^{2}$ )

(4) F (Farad)

Answer

Question. From NCERT

List-I

I. Joule

II. Watt

III. Volt

IV. Coulomb

List-II

A. Henry × Amp/sec

B. Farad × Volt

C. Coulomb × Volt

D. Oersted × cm

E. Amp × Gauss

F. Amp2 × Ohm

[This question includes concepts from 12th syllabus]

Codes:

(1) $I - A, I I - F, I I I - E, I V - D$

(2) $I - C, I I - F, I I I - A, I V - B$

(3) $I - C, I I - F, I I I - A, I V - E$

(4) $I - B, I I - F, I I I - A, I V - C$

Answer

Question.From NCERT PMT - 1997

Which relation is wrong?

(1) 1 Calorie = 4.18 Joules

(2) $1 Å = 10^{- 10} m$

(3) $1 M e V = 1 .6 \times 10^{- 13} J o u l e s$

(4) $1 N e w t o n = 10^{- 5} D y n e s$

Answer

Question.From NCERT

Match the following:

List-I		List-II
(a)	Distance between earth and stars	1.	Microns
(b)	Inter-atomic distance in a solid	2.	Angstroms
(c)	Size of the nucleus	3.	Light years
(d)	Wavelength of infrared laser	4.	Fermi
		5.	Kilometres

Codes:

	a	b	c	d
(1)	5	4	2	1
(2)	3	2	4	1
(3)	5	2	4	3
(4)	3	4	1	2

Answer

Question.

Answer

Question.

Answer

Question.From NCERT

Dyne/cm2 is not a unit of :

(1) Pressure

(2) Stress

(3) Strain

(4) Young's modulus

Answer

Question.From NCERT PMT - 2000

The units of angular momentum are

(1) $k g - m^{2} / s^{2}$

(2) $J o u l e - s$

(3) $J o u l e / s$

(4) $k g - m - s^{2}$

Answer

This product of moment of inertia and angular velocity yields kg⋅m2⋅s−1 or the joule-second.

Ans is 2

Question. From NCERT

The S.I. unit of gravitational potential is

(1) J

(2) $J - k g^{- 1}$

(3) $J - k g$

(4) $J - k g^{- 2}$

Answer

Correct option is

Joule/kg

The gravitational potential at a point is

the potential energy associated with a unit mass

due to its position in the gravitational field of another body.

Gravitational potential is the amount of work done in bringing a

body of unit mass from infinity to that point.
Gravitational potential (V) $= \frac{W o r k d o n e}{M a s s} = \frac{W}{m}$
Gravitational potential is a scalar quantity and the

SI unit is $J / k g$ .

Question.From NCERT

The unit of L/R is (where L = inductance and R = resistance)

(1) sec

(2) sec–1

(3) Volt

(4) Ampere

Answer

Correct option is

sec

[L/R] is a time constant so its unit is Second.

Question.

SI unit of permittivity is:

(1) $C^{2} m^{2} N^{- 1}$

(2) $C^{- 1} m^{2} N^{- 2}$

(3) $C^{2} m^{2} N^{2}$

(4) $C^{2} m^{- 2} N^{- 1}$

Answer

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Class 11 | Physics | chapter 1 | Units And Measurements Important MCQs *

[MLT−3k−1]

The dimension of 21​ε0​E2 (ε0​ is the permittivity of free space and E is electric field), is

[ML2T−1]

[ML−1T−2]

[ML2T−2]

[MLT−1]

[ML−1T−2]

We know that the given equation gives the energy

density for a capacitor. Dimensions of energy density

can be found as Electrical Energy divided by

Volume, or L3ML2T−2​=ML−1T−2

Newton–second (N⋅s) is the unit of

Velocity

Angular momentum

Momentum

Energy

Momentum

We know that:Impulse=change in momentum=F×t. So the unit of momentum will be equal to Newton−sec.

Which one of the following quantities has not been expressed in proper units ?

StrainStress​=N/m2

Surface tension=N/m

Energy=kg−m/s

Pressure= N/m2

Energy=kg−m/s

Stress has the units of Force/Area = N/m2,

while strain (=Δl/l) is dimensionless. So option A is correct.Surface tension is Force/Length, thus N/m, hence B is also correct.Energy has the units of [ML2T−2], hence the units have to be kgm2/s2. Thus C is incorrect option.Pressure is Force/Area = N/m2, thus D is again correct.

Wm−2K−4

Stefan's law is E=σ(T4)⇒σ=T4E​where,E=Area×TimeEnergy​=m2Watt​σ=k4Watt−m2​=Watt−m−2k−4

Angular momentum

Joule is a unit of energy and second

Energy

The electron volt (symbol eV; also written electronvolt)

is a unit of energy equal to approximately

1.602×10−19 joule (SI unit J).

By definition, it is the amount of energy gained by the charge of a single electron moved across an electric potential difference of one volt.Hence, the correct option is B

None of these

Temperature is a fundamental quantity,

so it can not be expressed as a

derived quantity in terms of length, mass and time.The correct option is D.

Electric field intensity

The electric field intensity is given as:E=−dxdV​Its unit is volts/metre

Henry

The self-inductance of a coil is given as:L=Iϕ​=AWb​=Henry

quantity of electricity

Ampere-hour is the unit of quantity of electricity or quantity of electric charge.Power is measured in Watt.Energy is measured in Joules.Strength of current ia measured in Amperes.

Mega electron volt (MeV)

Atomic energies are of order of electron volts and kilo electron volts but binding energy of nucleus that is energy required to keep the nucleus together has very high magnitude. It is of the order of Mega electron volt.

orbital motion of the earth around the sun

Universal Time (UT) is a time standard based on Earth's rotation.

Based on the rotation of the Earth, time can be measured by

observing celestial bodies crossing the meridian every day.

Astronomers found that it was more accurate to establish time

by observing stars as they crossed a meridian rather than by

observing the position of the Sun in the sky. The rotation of the

Earth and UT are monitored by the International Earth Rotation

and Reference Systems Service (IERS).

The unit of e.m.f. of a cell is:

dyne

volt

ampere

joule

volt

Electromotive force or e.m.f is defined as the battery's

energy per Coulomb of charge passing through it.

like other measures of energy per charge emf has

SI unit of volts , equivalent to joules per coulomb.

Self-inductance of a coil is defined as the phenomenon due to which an emf is induced in a coil when the magnetic flux of coil , linked with the coil changes or current in coil changes . Its S.I. unit is Henry(H)

Joule/kg

The gravitational potential at a point is

the potential energy associated with a unit mass

due to its position in the gravitational field of another body.

Gravitational potential is the amount of work done in bringing a

body of unit mass from infinity to that point.Gravitational potential (V) =MassWorkdone​=mW​Gravitational potential is a scalar quantity and the

SI unit is J/kg.

sec

[L/R] is a time constant so its unit is Second.

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$[M L T^{- 3} k^{- 1}]$

The dimension of $\frac{1}{2} ε_{0} E^{2}$ ( $ε_{0}$ is the permittivity of free space and $E$ is electric field), is

$[M L^{2} T^{- 1}]$

$[M L^{- 1} T^{- 2}]$

$[M L^{2} T^{- 2}]$

$[M L T^{- 1}]$

$[M L^{- 1} T^{- 2}]$

Volume, or $\frac{M L ^{2} T ^{- 2}}{L ^{3}} = M L^{- 1} T^{- 2}$

$N e w t o n - s e c o n d (N \cdot s)$ is the unit of

We know that:
$I m p u l s e = c h a n g e i n m o m e n t u m = F \times t$ .

So the unit of momentum will be equal to $N e w t o n - s e c$ .

$\frac{S t r e s s}{S t r a i n} = N / m^{2}$

$S u r f a c e t e n s i o n = N / m$

$E n e r g y = k g - m / s$

$P r e s s u r e =$ $N / m^{2}$

$E n e r g y = k g - m / s$

Stress has the units of Force/Area = $N / m^{2}$ ,

$W m^{- 2} K^{- 4}$

Stefan's law is $E = σ (T^{4})$
$\Rightarrow σ = \frac{E}{T ^{4}}$

where, $E = \frac{E n e r g y}{A r e a \times T i m e} = \frac{W a t t}{m ^{2}}$

$σ = \frac{W a t t - m ^{2}}{k ^{4}} = W a t t - m^{- 2} k^{- 4}$

1.602 $\times$ 10 $^{- 19}$ joule (SI unit J).

By definition, it is the amount of
energy gained by the charge of a
single electron moved across an
electric potential difference of one volt.

Hence, the correct option is $B$

derived quantity in terms of length, mass and time.
The correct option is D.

The electric field intensity is given as:
$E = - \frac{d V}{d x}$

Its unit is $v o l t s / m e t r e$

The self-inductance of a coil is given as:
$L = \frac{ϕ}{I}$

$= \frac{W b}{A} = H e n r y$

Ampere-hour is the unit of quantity of electricity or quantity of electric charge.
Power is measured in Watt.
Energy is measured in Joules.
Strength of current ia measured in Amperes.

Self-inductance of a coil is defined as the phenomenon due to which an emf is induced in a coil when the magnetic flux of coil , linked with the coil changes or current in coil changes . Its S.I. unit is $H e n r y (H)$

body of unit mass from infinity to that point.
Gravitational potential (V) $= \frac{W o r k d o n e}{M a s s} = \frac{W}{m}$
Gravitational potential is a scalar quantity and the

SI unit is $J / k g$ .