The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is: 1. θ = tan − 1 ( 1 4 ) θ=tan-114 2. θ = tan − 1 ( 4 ) θ=tan-14 3. θ = tan − 1 ( 2 ) θ=tan-12 4. θ = 45 0 θ=450

 

  Question:  From NCERT  | NEET PYQ 2012   || [Difficult level:Easy]  |Motion In A Plane| 

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is:

1. $\theta ={\tan }^{-1}\left(\frac{1}{4}\right)$

2. $\theta ={\tan }^{-1}\left(4\right)$

3. $\theta ={\tan }^{-1}\left(2\right)$

4. $\theta ={45}^0$

θ=450_

:2. 

$\theta ={\tan }^{-1}\left(4\right)$

.

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NCERT REFERENCE

CLASS 11 | Physics |CHAPTER 4 | Motion In A Plane

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