The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is A 0.9 B 0.7 C 0.5 D 1.1 Medium

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Question: From NCERT | AIIMS 2013 || [Difficult level:Medium] Subtopic:Energy Bands ||

:

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than $2480 n m$ is incident on it. The band gap (in $e V$ ) for the semiconductor is

$0.9$

$0.7$

$0.5$

$1.1$

Medium

Answer: .Correct option is C)

Band gap, $E_{g} = \frac{h c}{λ} = \frac{( 6 . 6 3 \times 1 0 ^{- 34} ) ( 3 \times 1 0 ^{8} )}{2 4 8 0 \times 1 0 ^{- 9} \times 1 . 6 \times 1 0 ^{- 19}} e V = 0.5 e V$

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The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is A 0.9 B 0.7 C 0.5 D 1.1 Medium

:

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than $2480 n m$ is incident on it. The band gap (in $e V$ ) for the semiconductor is

$0.9$

$0.7$

$0.5$

$1.1$

Band gap, $E_{g} = \frac{h c}{λ} = \frac{( 6 . 6 3 \times 1 0 ^{- 34} ) ( 3 \times 1 0 ^{8} )}{2 4 8 0 \times 1 0 ^{- 9} \times 1 . 6 \times 1 0 ^{- 19}} e V = 0.5 e V$

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The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is A 0.9 B 0.7 C 0.5 D 1.1 Medium

:

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is

0.9

0.7

0.5

1.1

Band gap, Eg​=λhc​=2480×10−9×1.6×10−19(6.63×10−34)(3×108)​eV=0.5 eV

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The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than $2480 n m$ is incident on it. The band gap (in $e V$ ) for the semiconductor is

$0.9$

$0.7$

$0.5$

$1.1$

Band gap, $E_{g} = \frac{h c}{λ} = \frac{( 6 . 6 3 \times 1 0 ^{- 34} ) ( 3 \times 1 0 ^{8} )}{2 4 8 0 \times 1 0 ^{- 9} \times 1 . 6 \times 1 0 ^{- 19}} e V = 0.5 e V$