For a transistor amplifier in common emitter configuration for load impedance of 1k􀀺 (hfe 􀀠 50 and hoe 􀀠 25􀁐s) the current gain is (a) – 24.8 (b) – 15.7 (c) – 5.2 (d) – 48.78

    

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For a transistor amplifier in common emitter configuration for load impedance of 1 k ( hfe​ = 50 and hoe​ = 25×10−6) the current gain is

A

-48.78

B

-15.7

C

-24.8

D

-5.2

Answer:

Transistor 

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