A small block slides without friction down an inclined plane starting from rest. Let S n ​ be the distance travelled from time t=(n−1)tot=n. The S n+1 ​ S n ​ ​ is. [ NEET 2021 ]

 

 Question: [Difficult level: Easy] From NCERT NEET 2021

A small block slides without friction down an inclined plane starting from rest. Let $S_n$ be the distance travelled from time $t=\left(n-1\right)tot=n$. The $\frac{S_n}{S_{n+1}}$ is.

A

$\frac{\left(2n-1\right)}{2n}$

B

$\frac{\left(2n+1\right)}{\left(2n-1\right)}$

C

$\frac{\left(2n-1\right)}{\left(2n+1\right)}$

D

(2n+1)(2n)​

Answer:C

$\frac{\left(2n-1\right)}{\left(2n+1\right)}$