From NCERT NEET - 2020
A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale.
The pitch of the screw gauge is:
(1) 0.25 mm
(2) 0.5 mm
(3) 1.0 mm
(4) 0.01 mm
Answer:
The pitch of the screw guage is given as:
p=least count×no. of divisions
Substitute the values:
p=0.01 mm×50
p=0.5 mm
