Question. Newton’s First Law of Motion-XIth NCERT Pg - 92

Physical independence of force is a consequence of
(a) third law of motion
(b) second law of motion
(c) first law of motion
(d) all of these laws (1991)

Answer

XIth NCERT Pg - 92

Question. Impulse-XIth NCERT Pg - 96

The force F acting on a particle of mass m is indicated by the force-time graph as shown. The change in momentum of the particle over the time interval from zero to 8 s is

(a) 24 N s (b) 20 N s (c) 12 N s (d) 6 N s (2014)

Answer

Impulse = Change in momentum = Area under F-t graph in that interval = Area of DABC – Area of rectangle CDEF + Area of rectangle = 12 N s

XIth NCERT Pg - 94

Question. Momentum-XIth NCERT

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by
(a) 68% (b) 41% (c) 200% (d) 100% (Mains 2012)

Answer

Question. Force , pg-95 XIth NCERT

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Question. Impulse-XIth NCERT Pg - 96

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Question.Newton’s Third Law of Motion-XIth NCERT Pg - 98 figure-5.6

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Question.Newton’s Third Law of Motion-XIth NCERT Pg - 98 figure-5.6

A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is

(a) MV (b) 1.5MV (c) 2MV (d) zero (2011

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Question.Conservation of Momentum-XIth NCERT Pg - 99

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Question.Conservation of Momentum-XIth NCERT Pg - 99

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Question.Equilibrium of a Particle-XIth NCERT Pg - 100

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Question.Common Forces in Mechanics--XIth NCERT Pg - 102

Which one of the following statements is incorrect?
(a) Rolling friction is smaller than sliding friction.
(b) Limiting value of static friction is directly proportional to normal reaction.
(c) Frictional force opposes the relative motion.
(d) Coefficient of sliding friction has dimensions of length. (NEET 2018)

Answer

(d) : Coefficient of sliding friction has no dimension.

Question.-Friction-XIth NCERT Pg - 102

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Question.Common Forces in Mechanics--XIth NCERT Pg - 102

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Question.

A block $A$ of mass $m_{1}$ rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block $B$ of mass $m_{2}$ is suspended. The coefficient of kinetic friction between the block and the table is $μ_{k}$ . When the block $A$ is sliding on the table, the tension in the string is:

$\frac{m _{1} m _{2} ( 1 + μ _{k} ) g}{m _{1} + m _{2}}$

$\frac{m _{1} m _{2} ( 1 - μ _{k} ) g}{m _{1} + m _{2}}$

$\frac{( m _{2} + μ _{k} m _{1} ) g}{( m _{1} + m _{2} )}$

$\frac{( m _{2} - μ _{k} m _{1} ) g}{( m _{1} + m _{2} )}$

Answer

Correct option is

$\frac{m _{1} m _{2} ( 1 + μ _{k} ) g}{m _{1} + m _{2}}$

The blocks $m_{1}$ and $m_{2}$ will move with combined acceleration a:
From F.B.D. of block $m_{1}$
$T - f_{1} = m_{1} a$ ...(i)
as the block $m_{1}$ is sliding, kinetic friction will be acting:
$T - μ_{k} N = m_{1} a$ ...(ii)
$N = m g$ ...(iii)
From F.B.D. of block $m_{2}$
$m_{2} g - T = m_{2} a$ ...(iv)
adding (ii) and (iv)
$a = \frac{m _{2} g - μ _{k} N}{m _{1} + m _{2}}$ ...(v)
$T = m_{2} g - m_{2} a = m_{2} (g - \frac{m _{2} g - μ _{k} N}{m _{1} + m _{2}})$
$= m_{2} (\frac{m _{1} g + μ _{k} m _{1} g}{m _{1} + m _{2}})$
$= m_{1} m_{2} (\frac{1 + μ _{k}}{m _{1} + m _{2}} g)$
hence correct answer is option A

Question.Common Forces in Mechanics--XIth NCERT Pg - 102

A conveyor belt is moving at a constant speed of 2 m s–1. A box is gently dropped on it. The coefficient of friction between them is m = 0.5. The distance that the box will move relative to belt before coming to rest on it, taking g = 10 m s–2, is

(a) 0.4 m (b) 1.2 m (c) 0.6 m (d) zero (Mains 2011)

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CLASS 11 | CHAPTER 5 | Laws of Motion-Types Of Questions | PHYSICS | NEET

Physical independence of force is a consequence of
(a) third law of motion
(b) second law of motion
(c) first law of motion
(d) all of these laws (1991)

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by
(a) 68% (b) 41% (c) 200% (d) 100% (Mains 2012)

$\frac{m _{1} m _{2} ( 1 + μ _{k} ) g}{m _{1} + m _{2}}$

$\frac{m _{1} m _{2} ( 1 - μ _{k} ) g}{m _{1} + m _{2}}$

$\frac{( m _{2} + μ _{k} m _{1} ) g}{( m _{1} + m _{2} )}$

$\frac{( m _{2} - μ _{k} m _{1} ) g}{( m _{1} + m _{2} )}$

$\frac{m _{1} m _{2} ( 1 + μ _{k} ) g}{m _{1} + m _{2}}$

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CLASS 11 | CHAPTER 5 | Laws of Motion-Types Of Questions | PHYSICS | NEET

Physical independence of force is a consequence of (a) third law of motion (b) second law of motion (c) first law of motion (d) all of these laws (1991)

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by (a) 68% (b) 41% (c) 200% (d) 100% (Mains 2012)

m1​+m2​m1​m2​(1+μk​)g​

m1​+m2​m1​m2​(1−μk​)g​

(m1​+m2​)(m2​+μk​ m1​)g​

(m1​+m2​)(m2​−μk​ m1​)g​

m1​+m2​m1​m2​(1+μk​)g​

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Physical independence of force is a consequence of
(a) third law of motion
(b) second law of motion
(c) first law of motion
(d) all of these laws (1991)

A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by
(a) 68% (b) 41% (c) 200% (d) 100% (Mains 2012)

$\frac{m _{1} m _{2} ( 1 + μ _{k} ) g}{m _{1} + m _{2}}$

$\frac{m _{1} m _{2} ( 1 - μ _{k} ) g}{m _{1} + m _{2}}$

$\frac{( m _{2} + μ _{k} m _{1} ) g}{( m _{1} + m _{2} )}$

$\frac{( m _{2} - μ _{k} m _{1} ) g}{( m _{1} + m _{2} )}$

$\frac{m _{1} m _{2} ( 1 + μ _{k} ) g}{m _{1} + m _{2}}$